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How much energy does it take to move a particle with a charge of +2 nC, from an initial position infinitely far from a second particle with a charge of +3 mC, to a final position 0.20 m from the second particle?

User Fulrus
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1 Answer

2 votes

To solve this problem we will apply the concept related to the electric potential energy, defined from the laws of Coulomb for which it is necessary to,


U = (kq_1q_2)/(r)

Here,

k = Coulomb's constant


q_(1,2)= Charge of each object

r = Distance,

Our values are given as,


q_1 = 2nC = 2*10^(-9)


q_2 =3mC =3*10^(-3) C


r = 0.2m

Finally replacing we have that,


U = (kq_1q_2)/(r)


U = ((9*10^9)(2*10^(-9))(3*10^(-3)))/(0.2)


U = 0.27J

Therefore the energy necessary to move the particle is 0.27J

User SylvainJack
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