Question

2A1 + 3Cl2 → 2AICI:
a) How many moles of AICIz form when 3.2 mol of Cl2 reacts?

Answer 1

2.13 moles of AlCl3 are produced from 3.2 moles of Cl2

Step-by-step explanation:

Moles : The amount of substance that contain as many particles as present in 12 grams of C-12.

The balanced equation for the reaction is :

`2Al +3Cl_(2)\rightarrow 2AlCl_(3)`

This reaction shows the following :

2 mole Al = 3 mole Cl2 = 2 mole AlCl3

In question we are asked to calculate the moles of AlCl3 produced from Cl2

So, we will use only Cl2 andAlCl3 moles

3 mole Cl2 = 2 mole AlCl3

1 moles of Cl2 will give =

`(2)/(3)` of AlCl3

3.2 moles of Cl2 will give =

`(2)/(3)* 3.2` of AlCl3

= 2.133 moles