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An ideal gas undergoes an expansion from the initial state described by Pi, Vi, T to a final state described by Pf, Vf, T in (a) a process at the constant external pressure Pf, and (b) in a reversible process. Derive expressions for the largest mass that can be lifted through a height h in the surroundings in these processes.

1 Answer

6 votes

Answer:

A) m =
(p_f(V_f-V_i))/(gh)

B) m =
- n R T (ln (V_f )/(V_i))(1)/(gh)

Step-by-step explanation:

A) a process at the constant external pressure Pf,

We Know that

W = mgh-------------------------(1)

W=
p \Delta V---------------------------(2)

Equating (1) and(2)

mgh =
p \Delta V

=
p_f (V_f-V_i)

Therefore m =
(p_f(V_f-V_i))/(gh)

B)In a irreversible process

W = mgh----------------------(3)


\mathrm{W}=-\int_{V_(i)}^{V_(f)} \mathrm{P} d V---------------------(4)

PV =nRT

P =
(nRT)/(V)


\mathrm{W}=-\int_{V_(i)}^{V_(f)} \frac{\mathrm{nRT}}{V} d V

W =
-n R T \int_{V_(i)}^{V_(f)} (d V)/(V)

W=
- n R T (ln V_i- ln V_f)

W=
- n R T (ln V_f- ln V_i)

W=
- n R T( ln (V_f )/( V_i))

From EQ(3)

mgh=
- n R T( ln (V_f )/( V_i))

m =
- n R T (ln (V_f )/(V_i))(1)/(gh)

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