Answer:
The answer to your question is 4.14 g of O₃
Step-by-step explanation:
Data
mass of nitrogen dioxide = 3.97 g
mass of ozone = x g
Reaction
NO₂ (g) + O₂ (g) ⇒ NO (g) + O₃ (g)
- Check that that reaction is balanced
Reactants Elements Products
1 N 1
4 O 4
This reaction is balanced
- Calculate the molecular mass of NO₂ and O₃
NO₂ = 14 + 32 = 46 g
O₃ = 48 g
- Calculate the mass of Ozone formed.
46 g of NO₂ ------------------ 48 g of O₃
3.97 gof NO₂ ---------------- x
x = (3.97 x 48 ) / 46
x = 190.56 / 46
x = 4.14 g of O₃