Question

Find the value of x in the triangle below

Answer 1

The figure is a right angled triangle , where the value 4 is perpendicular , 8 is base and x is hypotenuse.

So, By Pythagoras theorem

`x {}^(2) = 4 {}^(2) + 8 {}^(2)`

`x = √(16 + 64)`

`x = √(80)`

Answer 2

• √80 (Option A)

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Explanation:

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• This is Right Angled Triangle.

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We'll solve this using the Pythagorean Theorem.

Let,

• x be AC, where AC is the Hypotenuse.

• 4 be AB, where AB is the Perpendicular.

• 8 be BC, where BC is the Base

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We know that,

`{ \longrightarrow \pmb{ \qquad (AC) {}^(2) = (AB) {}^(2) +( BC) {}^(2) }}`

`{ \longrightarrow \sf{ \qquad (x) {}^(2) = (4) {}^(2) +( 8) {}^(2) }}`

`{ \longrightarrow \sf{ \qquad (x) {}^(2) = 16 +64 }}`

`{ \longrightarrow \sf{ \qquad (x) {}^(2) = 80 }}`

`{ \longrightarrow \it\pmb{ \qquad x {} = √(80) }}`

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Therefore,

• The value of x is √80