Answer:
(D) 70
Explanation:
We have been given that 5 of the 12 temporary employees are women.
So the number of men will be
.
We are asked to find the number of possible groups of 4 temporary employees that consist of 3 women and 1 man.
Since there are 5 women, so we can select 3 women from 5 women is
ways.
![5C3=(5!)/(3!(5-3)!)](https://img.qammunity.org/2021/formulas/mathematics/high-school/shde44l29o99g8jyi4lpmuijxow03sbohv.png)
![5C3=(5*4*3*2!)/(3*2*1*2!)](https://img.qammunity.org/2021/formulas/mathematics/high-school/mlha35t1hox4a4sjvlohgq1ewyoior7jdn.png)
![5C3=(5*2*3)/(3)](https://img.qammunity.org/2021/formulas/mathematics/high-school/73v52aicxe2se2jh585euryzg8wb0ru5sj.png)
![5C3=10](https://img.qammunity.org/2021/formulas/mathematics/high-school/ec7gqjjaiyx2i945x1oiwlxuh83l5ojbnz.png)
Since there are 7 men, so we can select 1 man from 7 men is
ways.
![7C1=(7!)/(1!(7-1)!)](https://img.qammunity.org/2021/formulas/mathematics/high-school/todlug2vyesgjgqo7axp3jyzefwsxk3y6d.png)
![7C1=(7*6!)/(1*6!)](https://img.qammunity.org/2021/formulas/mathematics/high-school/weimkde9cp4ps1q8iuiqggnokbrc3ue1sm.png)
![7C1=7](https://img.qammunity.org/2021/formulas/mathematics/high-school/jy1mzq2p8piimgur3qkb94dsx5b2n25i2d.png)
Total groups of 4 temporary employees consisting 3 women and 1 man would be
![10*7=70](https://img.qammunity.org/2021/formulas/mathematics/high-school/ourhj70ggb9kggoecgb44c0ju38lbb66z3.png)
Therefore, there are 70 possible groups of 4 temporary employees consisting 3 women and 1 man.