Answer:
0.572 Hz
Step-by-step explanation:
given,
length of simple pendulum, l = 0.76 m
mass of the bob, m = 365 g = 0.365 Kg
angle made from the vertical, = 12°
frequency, f = ?
![f = (1)/(2\pi)\sqrt{(g)/(L)}](https://img.qammunity.org/2021/formulas/physics/high-school/nyefjwdppu9au6g4rqrwefoe1cr3ihh2ba.png)
![f = (1)/(2\pi)\sqrt{(9.8)/(0.76)}](https://img.qammunity.org/2021/formulas/physics/high-school/6lpw0eljs3k77z289lc4cb08fqdp8520y0.png)
![f = (1)/(2\pi)* 3.59](https://img.qammunity.org/2021/formulas/physics/high-school/f4il6lb9rg6hm2y23rvjcxxfz8qtw0pnxz.png)
f = 0.572 Hz
The frequency at which pendulum vibrates is equal to 0.572 Hz