Question

What is the equation of the line that is parallel to y=6x−1 and passes through the point (−3,4)?

The equation will be in slope-intercept form.


A. y=−6x+5
B. y=−16x−7
C. y=−16x−5
D. y=6x−14
E. y=6x+22

Answer 1

E. y=6x+22

Explanation:

Because it is parallel, it will have the same slope. You can eliminate A,B, and C. If you plug in (-3,4 into option D, it would not work. If you plug it in for option E, it would work.

y=6x+22

y=6(-3) +22

y=-18+22

y=4

Answer 2

Answer: y = 6x + 22

Explanation:

Parallel lines have same slope. So, a line parallel to y = 6x − 1 is y = 6x + c.

Now to find c, put (-3,4) to this equation since the line passes through the point.

4 = 6 × -3 + c

4 = -18 + c

4 + 18 = c

c = 22

So, equation is y = 6x + 22