Question

How do you find DE, Round to nearest 10th

Answer 1

Answer:
`DE\approx6.0`

Explanation:

Observe in the figure given in the exercise that four right triangles are formed.

In this case you can use the following Trigonometric Identity to solve this exercise:

`cos\alpha=(adjacent)/(hypotenuse)`

From the figure you can identify that:

`\alpha =53\°\\\\hypotenuse=10\\\\adjacent=BE=DE`

Then, you can substitute values:

`cos(53\°)=(DE)/(10)`

The next step is to solve for DE in order to find its value. This is:

`10*cos(53\°)=DE\\\\DE=6.01`

Finally, rounding the result to the nearest tenth, you get that this is:

`DE\approx6.0`