Question

A bullet with a mass of 4.69 g and a speed of 839 m/s penetrates a tree horizontally to a depth of 3.98 cm. Assume that a constant frictional force stops the bullet. Calculate the magnitude of this frictional force. Try energy considerations

Answer 1

Force will be equal to 41474.723 N

Step-by-step explanation:

We have given mass of the bullet
`m=4.69gram=4.69* 10^(-3)kg`

Speed of the bullet
`v=839m/sec`

So kinetic energy
`KE=(1)/(2)mv^2=(1)/(2)* 4.69* 10^(-3)* 839^2=1650.694J`

Depth is given d = 3.98 cm = 0.0398 m

Let the horizontal force is F

So from work energy theorem

`Fs=1650.694`

`F* 0.0398=1650.694`

`F=41474.723N`