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Hydrogen sulfide decomposes according to the following reaction:__________2 H2S(g) 2 H2(g) + S2(g)For this reaction at 298K ÎS° = 78.1 J/K, ÎH° = 169.4 kJ, and ÎG° = 146.1 kJ. What is the value of ÎG° at 900 K?a. -69881 kJb. 240 kJc. 48.4 kJd. 441 kJe. 99.1 kJ

User Iqstatic
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Answer:

e. ΔG = 99,1 kJ

Step-by-step explanation:

For the reaction:

2H₂S(g) → 2H₂(g) + S₂(g)

It is possible to obtain the ΔG at 900K using:

ΔG = ΔH - TΔS

As ΔH is 169,4 kJ and ΔS is 0,0781kJ/K:

ΔG = 169,4 kJ - 900K×0,0781kJ/K

e. ΔG = 99,1 kJ

I hope it helps!

User Veinhorn
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