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What is the range of the function f(x) = 3x^2 + 6x - 8?

What is the range of the function f(x) = 3x^2 + 6x - 8?-example-1

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Answer:

Step-by-step explanation:

We will first need to find the coordinates of the turning point of the parabola, and here is how:

First use x= -b/2a to determine the axis of symmetry (which is also the x coordinate).

x=-6/2(3)
x=-1

Now that we have the x value, we can substitute it into the quadratic equation to get its corresponding y value:

f(-1) = 3(-1)^2 + 6(-1) - 8
y = -11

Because -11 is the lowest y value of the graph, your range is:

y >= -11
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