18.5k views
2 votes
Carl drew a rectangle with a width of 8 in. And a length of 32 in. Which rectangles are not similar to Carl’s rectangle? Select ALL that apply.

Carl drew a rectangle with a width of 8 in. And a length of 32 in. Which rectangles-example-1
User Rabih Harb
by
5.5k points

1 Answer

0 votes

Answer:

1) A rectangle with width of 10 cm and length of 44 cm.

4) A rectangle with width of 9 mm and length of 45 cm.

Explanation:

Given:

Length of the rectangle = 32 in.

Width of the rectangle = 8 in.

Now we will find the ratio of length by width.


(length)/(width)= (32)/(8) = (4)/(1) \ \ \ \ equation \ 1

Now we need to find from the given Option which rectangles are not similar to Carl's Rectangle.

So we will check for each.

1) A rectangle with width of 10 cm and length of 44 cm.

Now we will find the ratio of length by width.


(length)/(width)= (44)/(10) = (11)/(5) \ \ \ \ equation \ 2

Now we know that;

"When ratio of the dimension of corresponding rectangles are equal then the 2 rectangles are said to be similar."

Now Comparing equation 1 and equation 2 we get;

equation 1
\\eq equation 2

Hence This rectangle is not similar to Carl's rectangle.

2) A rectangle with width of 2.5 inch and length of 10 inch.

Now we will find the ratio of length by width.


(length)/(width)= (10)/(2.5) = (4)/(1) \ \ \ \ equation \ 2

Now we know that;

"When ratio of the dimension of 2 corresponding rectangles are equal then the 2 rectangles are said to be similar."

Now Comparing equation 1 and equation 2 we get;

equation 1
= equation 2

Hence This rectangle is similar to Carl's rectangle.

3) A rectangle with width of 23 cm and length of 92 cm.

Now we will find the ratio of length by width.


(length)/(width)= (92)/(23) = (4)/(1) \ \ \ \ equation \ 2

Now we know that;

"When ratio of the dimension of 2 corresponding rectangles are equal then the 2 rectangles are said to be similar."

Now Comparing equation 1 and equation 2 we get;

equation 1
= equation 2

Hence This rectangle is similar to Carl's rectangle.

4) A rectangle with width of 9 mm and length of 45 cm.

Now we will find the ratio of length by width.


(length)/(width)= (45)/(9) = (5)/(1) \ \ \ \ equation \ 2

Now we know that;

"When ratio of the dimension of corresponding rectangles are equal then the 2 rectangles are said to be similar."

Now Comparing equation 1 and equation 2 we get;

equation 1
\\eq equation 2

Hence This rectangle is not similar to Carl's rectangle.

User Lanqy
by
5.6k points