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V(t) = 2000 - 40t + .2t^2. How fast is the volume changing when t=40 seconds?The answer is -24in^3/sec but I need the work that goes with that.

User Sassa
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1 Answer

3 votes

Answer:

-24 in^3/sec

Explanation:


V(t) = 2000 - 40t + .2t^2

we need to find the rate of change of volume


(dV)/(dt) = (d)/(dt) (2000 - 40t + .2t^2)

Apply power rule to take dervative


(dV)/(dt) = -40+0.4t

we need to find out dv/dt when t=40

Substitute 40 for t


(dV)/(dt) = -40+0.4t


(dV)/(dt) = -40+0.4(40)


(dV)/(dt) = -40+16


(dV)/(dt) =-24

so its -24 in^3/sec

User Manish Mulimani
by
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