Answer:
Step-by-step explanation:
a) Chemical equation:
2Mg + CO₂ → 2MgO + C
b)
Mass of magnesium = 10.0 g
Mass of carbon produced = ?
Solution:
Number of moles of magnesium = mass/ molar mass
Number of moles = 10.0 g/ 24 g/mol
Number of moles = 0.42 mol
Now we will compare the moles of magnesium and carbon.
Mg : C
2 : 1
0.42 : 1/2×0.42 = 0.21 mol
Mass of carbon:
Mass = number of moles × molar mass
Mass = 0.21 mol × 12 g/mol
Mass = 2.52 g
C)
Number of moles of magnesium = mass/ molar mass
Number of moles = 10.0 g/ 24 g/mol
Number of moles = 0.42 mol
Now we will compare the moles of magnesium and carbon dioxide.
Mg : CO₂
2 : 1
0.42 : 1/2×0.42 = 0.21 mol
Mass of carbon dioxide:
Mass = number of moles × molar mass
Mass = 0.21 mol × 44 g/mol
Mass = 9.24 g
d)
Volume of carbon dioxide:
PV = nRT
V = nRT/P
V = 0.21 mol ×0.0821 atm. L / mol.k × 273 k / 1 atm
V = 4.71 L