Question

How long does it take to send a 3 MiB file from Host A to Host B over a circuit-switched network, assuming:

Total link transmission rate = 30.8 Gbps.
Network is FDM, with 2 permitted users, each with an equal bandwidth share.
A link connection requires a setup time of 67.7 ms.

Answer 1

The answer is 69.3 ms

Step-by-step explanation:

if 1 MiB = 0.008388608 Gb

then 3 MiB = 3 x 0.008388608 = 0.025165824 Gb.

since the bandwidth is equally shared amongst two users, each user gets equal share of the bandwidth which is Total Bandwidth/Number of Users.(

The bandwidth for each user = 30.8/2 = 15.4 Gbps.

The time taken for the message to reach from host A to host B = 0.025165824/15.4 s = 0.00163414441 which is = 1.63 ms.

The link connection requires a setup time of 67.7 ms

Therefore, the net time required is = 67.7 ms +1.63 ms = 69.3 ms.