Question

Acceleration = change of velocity divided by time interval = Δv/Δt.

Find the acceleration of a car that can go from rest to 120 km/h in 14 s.

Answer 1

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Step-by-step explanation:

A = 2.378M/S^2

Answer 2

a=2.378 m/s^2

Step-by-step explanation:

a=Δv/Δt------eq(1)

Δv=Vf-Vi=120 km/h-0 km/h=120 km/h

or Δv=33.3 m/sec

or time=t=14s

putting values in eq(1)

a=33.3/14

a=2.378 m/s^2