Question

A container with a volume of 623 L and holds nitrogen gas with a pressure of 111 atm. How many moles of gas does it contain at 12.00 °C? Assume ideal gas behavior L atm Use R = 0.08206- , for the ideal gas constant Use-273.15° C for absolute zero. . Report your answer in scientific notation and round to three significant figures L5ecs mol K Provide your answer below: mol MORE INSTRUCTIO FEEDBACK

Answer 1

The container contains 2.96 *10³ moles nitrogen

Step-by-step explanation:

Step 1: Data given

Volume of the container = 623 L

Pressure of nitrogen gas = 111 atm

Temperature = 12.00°C

Step 2: Calculate number of moles

p*V = n*R*T

n = (p*V)/(R*T)

⇒ with n = the number of nitrogen gas = TO BE DETERMINED

⇒ with p = the pressure of the gas = 111 atm

⇒ with V = the volume of the container = 623 L

⇒ with R = the gas constant = 0.08206 L*atm/mol*K

⇒ with T = the temperature = 12.00 °C = 273+12 = 285 Kelvin

n = (111 * 623)/(0.08206*285)

n = 2956.9 moles

The container contains 2956.9 = 2.96 *10³ moles nitrogen