Question

An airplane is flying in a horizontal circle at a speed of 92.1 m/s. The 55.6 kg pilot does not want his radial acceleration to exceed 8.45 g. The acceleration of gravity is 9.8 m/s². What is the minimum radius of the circular path?

Answer 1

r = 102.43 m

Step-by-step explanation:

Newton's second law for this case is

F = ma

Where the acceleration is centripetal

a = v² / r

r = v² / a

They indicate that the radial acceleration is 8.45 g

r = v² / 8.45 g.

r = 92.1² / 8.45 9.8

r = 102.43 m