Question

A 12.2-m-radius Ferris wheel rotates once each 28 s. (a) What is its angular speed (in radians per second)?(b) What is the linear speed of a passenger?___________m/s(c) What is the acceleration of a passenger?_____________m/s2

Answer 1

(a) 0.2165 rad/sec

(b) 2.6143 m /sec

(C)
`0.459rad/sec^2`

Step-by-step explanation:

It is given that wheel rotates each revolution in 29 sec

So time period T = 29 sec

(a) Angular speed is equal; to
`\omega =(2\pi )/(T)=(2* 3.14)/(29)=0.2165rad/sec`

(b) Radius is given r = 12.2 m

So linear velocity
`v=\omega r=0.2165* 12.2=2.6143m/sec`

(C) Angular acceleration is given by
`a=(v^2)/(r)=(2.6143^2)/(12.2)=0.459rad/sec^2`