Answer:
![V=97.6\ in^3](https://img.qammunity.org/2021/formulas/mathematics/middle-school/pxvvzfwpn9y2scs8b4fd4tlvej0qakr3ux.png)
Explanation:
step 1
Find the volume of the cylinder
The volume of the cylinder is equal to
![V=\pi r^(2)h](https://img.qammunity.org/2021/formulas/mathematics/middle-school/4na2k3gqhaf7wq0h0ytlnej9wluuuksq9k.png)
we have
---> the radius is half the diameter
![h=8\ in](https://img.qammunity.org/2021/formulas/mathematics/middle-school/iuxp6qjc9uomxqf3jazas8mvn5hmik3azi.png)
substitute
![V=\pi (2)^(2)(8)\\\\V=32\pi\ in^3](https://img.qammunity.org/2021/formulas/mathematics/middle-school/gwqdqjjkmrspyymk91gbzgx1jzc8q81po9.png)
step 2
Find the volume of the cone
The volume of the cone is equal to
![V=(1)/(3)\pi r^(2) h](https://img.qammunity.org/2021/formulas/mathematics/middle-school/948luugpbjx5ne8lqsno0zlguswa5fyl0a.png)
we have
we have
---> the radius is the same that the radius of the cylinder
![h=0.70\ in](https://img.qammunity.org/2021/formulas/mathematics/middle-school/2xqywj531mkvjz97h5l34us0x8dkb9gxso.png)
substitute
![V=(1)/(3)\pi (2)^(2) (0.70)\\\\V=0.93\pi\ in^3](https://img.qammunity.org/2021/formulas/mathematics/middle-school/u3t8jfjgdol2mjkj27pmesrbrucvqdwn2y.png)
step 3
Find the volume of the plastic object
we know that
The volume of the plastic object is equal to the volume of the cylinder minus the volume of the cone
so
![V=32\pi-0.93\pi=31.07\pi\ in^3](https://img.qammunity.org/2021/formulas/mathematics/middle-school/59dm1alpyaj3d3xslc8ufefgg3e2gro0qc.png)
assume
![\pi=3.1416](https://img.qammunity.org/2021/formulas/mathematics/middle-school/293528pzxwkmpnmm44291jkqlxbesfxjdh.png)
![V=31.07(3.1416)=97.6\ in^3](https://img.qammunity.org/2021/formulas/mathematics/middle-school/pxju12kemnhh4a0tvj4qig06ykzui1e71p.png)