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Consider the intermediate chemical reactions.

Ca(s) + CO2(g) + O2(g) - Cacos(s) AH, = -812.8 kJ
2 Ca(s)+ O2(g) → 2Cao(s)
AH, = - 1,269.8kJ
The final overall chemical equation is Cao(s) + CO2(g) → CaCO3(s). When the enthalpy of this overall chemical equation is
calculated, the enthalpy of the second intermediate equation
is halved and has its sign changed.
is halved.
has its sign changed.
is unchanged.

1 Answer

4 votes

Answer:

a) is halved and has its sign changed

Step-by-step explanation:

i took the quiz on edge it is correct :)

User EJ Mak
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