Answer:
110 rev
Step-by-step explanation:
Given:
v₀ = 32 m/s
v = 0 m/s
a = -2.25 m/s²
Find: Δx
v² = v₀² + 2aΔx
(0 m/s)² = (32 m/s)² + 2 (-2.25 m/s²) Δx
Δx = 228 m
The circumference of the tires is 2π × 0.32 m = 2.01 m. Therefore:
228 m × (1 rev / 2.01 m) = 110 rev