Question

32. Calculate How many kilojoules of heat are re-

quired to vaporize 50.0 g of ethanol, C2H60? The
boiling point of ethanol is 78.3°C. Its molar heat
of vaporization is 38.6 kJ/mol.

Answer 1

ΔH = 41.7 kj

Step-by-step explanation:

Given data:

Mass of ethanol = 50 g

Heat required to vaporize = ?

Boiling point of ethanol = 78.3°C

Molar heat of vaporization = 38.6 kj/mol

Solution:

First of all we will calculate the number of moles.

Number of moles = mass / molar mass

Number of moles = 50 g/ 46.07 g/mol

Number of moles = 1.08 mol

ΔH = 38.6 kj/mol ×1.08 mol

ΔH = 41.7 kj