Question

A potter’s wheel moves from rest to an angular speed of 0.10 rev/s in 20.2 s.

Assuming constant angular acceleration,
what is its angular acceleration in rad/s^2?
Answer in units of rad/s

Answer 1

0.031 rad/s²

Step-by-step explanation:

Given:

ω₀ = 0 rad/s

ω = 0.10 rev/s = 0.628 rad/s

t = 20.2 s

Find: α

ω = αt + ω₀

0.628 rad/s = α (20.2 s) + 0 rad/s

α = 0.031 rad/s²