Question

I have to find the angle measurements of a interior triangle a is 4x b is 7x-2 and c is 5x-10

Answer 1

To find the angle measurements of the interior triangle, set up an equation using the fact that the sum of the angles in a triangle is 180 degrees. Solve for x and substitute it back into the expressions for a, b, and c to find the angle measurements.

Step-by-step explanation:

To find the angle measurements of the interior triangle, we need to use the fact that the sum of the angles in a triangle is 180 degrees. Let's set up an equation:

4x + 7x-2 + 5x-10 = 180

Combining like terms, we have 16x - 12 = 180. Adding 12 to both sides, we get 16x = 192. Dividing both sides by 16 gives us x = 12. Now we can substitute this value back into the expressions for a, b, and c:

a = 4x = 4(12) = 48 degrees

b = 7x-2 = 7(12)-2 = 82 degrees

c = 5x-10 = 5(12)-10 = 50 degrees

So the angle measurements of the interior triangle are 48 degrees, 82 degrees, and 50 degrees.

Answer 2

`m\angle a=48^o\\m\angle b=82^o\\m\angle c=50^o`

Step-by-step explanation:

we know that

The sum of the interior angles in any triangle must be equal to 180 degrees

so

`m\angle a+m\angle b+m\angle c=180^o`

substitute the given values

`4x^o+(7x-2)^o+(5x-10)^o=180^o`

solve for x

`(16x-12)^o=180^o`

`16x=180+12\\16x=192\\x=12`

Find the angle measurements

`m\angle a=4(12)=48^o`

`m\angle b=7(12)-2=82^o`

`m\angle c=5(12)-10)=50^o`