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Kenya jumped 71/6 feet. Janet jumped 61/3. How much farther did Kanya jump?

User Vanarajcs
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1 Answer

4 votes

Question:

Kenya jumped 7 1/6 feet. Janet jumped 6 1/3 feet. How much farther did Kenya jump?

Answer:

Kenya jumped
(5)/(6) feet farther than Janet

Solution:

Kenya jumped =
7(1)/(6) \text{ feet }

Janet jumped =
6(1)/(3) \text{ feet }

We need to find how much farther did kenya jump

So we need to find the difference between kenya jump and janet jump

Let us first convert the mixed fractions to improper fractions

Multiply the whole number part by the fraction's denominator.

Add that to the numerator.

Then write the result on top of the denominator.


7(1)/(6) = (7 * 6 + 1)/(6) = (43)/(6)


6(1)/(3) = (3 * 6 + 1)/(3) = (19)/(3)

Now find the difference


difference = (43)/(6) - (19)/(3)\\\\\text{Make the denominators same }\\\\difference = (43)/(6) - (19 * 2)/(3 * 2)\\\\difference = (43)/(6) - (38)/(6)\\\\difference = (43-38)/(6) = (5)/(6)

Thus Kenya jumped
(5)/(6) feet farther than Janet

User CognizantApe
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