Question

16=2(-8t-1)(t-2) solve for t​

Answer 1

hi there! so here's my answer

`\rm \tiny\color{green}t = (10)/(9) \\ \\ \tt \: in \: alternative \: form \\ \\ \color{yellow} \rm \: t = 1 (1)/(9) \: \: \: or \: \: t = 1.1`

Explanation:

`\color{gray} \tt \: 16 = 2( - 8t - 1) * (t - 2)`

• calculate the difference

`\color{gray} \tt \: 16 = 2(- 9)(t - 2)`

• multiplying an odd number of negative terms makes the product negative

`\color{gray} \tt \: 16=^ \ 2*9(t-2)`

• multiply the numbers

`\color{gray} \tt \: 16=-18 (t-2)`

• distribute - 18 trough the parentheses

`\color{gray} \tt \: 16 = - 18t + 36`

• move the variable to the left hand side and change its sign

`\color{gray} \tt \:16+18t=36`

• move the constant to the right-hand side and change its sign

`\color{gray} \tt \:18t=36-16`

• substract

`\color{gray} \tt \:18t=20`

• by both sides of the equation by 18

`\:\rm \tiny\color{green}t = (10)/(9) \\ \\ \tt \: in \: alternative \: form \\ \\ \color{yellow} \rm \: t = 1 (1)/(9) \: \: \: or \: \: t = 1.1`

hope it helps