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Find the equation of the MN, where M(-2,2) and N(0,3) using the formulas y-y,=m(x-x) and m= y2-y1/x2-x1

Y=

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Answer:

Explanation:

M(-2,2) and N(0,3)

y2= 3, y1 = 2, x2 = 0, x1 = -2

Slope m = (y2-y1)/(x2-x1)

m = {3 - 2)/(0 + 2)

m = 1/2

The equation of line

y - y1 = m(x - x1)

y - 2 = 1/2(x + 2)

Multiply each term by 2

2y - 4 = x + 2

2y = x + 2 + 4

2y = x + 6

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