Question

Two thin conducting plates, each 25.0 cm on a side, are situated parallel to one another and 5.0 mm apart. If 10^?11 electrons are moved from one plate to the other,what is the electric field between the plates?

Answer 1

Answer:
`E=2.9* 10^3\ N/C`

Step-by-step explanation:

Given

Side of square plate
`L=25\ cm`

distance between plates
`d=5\ mm`

no of electron
`n=10^(11)\ electrons`

electron charge
`e=1.6* 10^(-19)\ C`

`\epsilon _0=8.85* 10^(-12)`

Electric field between plates is given by

`E=(\sigma )/(\epsilon _0)`

`E=((Q)/(A))/(\epsilon _0)`

`E=(ne)/(A\epsilon _0)`

`E=(10^(11)* 1.6* 10^(-19))/(0.25^2* 8.85* 10^(-12))`

`E=2.9* 10^3\ N/C`