Question

Need help solving
-3^4x-3^4/(-3^2)^3

Answer 1

The solved given expression is

`(-3^4x-3^4)/((-3^2)^3)=-((x+1))/(9)`

Explanation:

Given expression is
`(-3^4x-3^4)/((-3^2)^3)`

To solving the given expression as below :

`(-3^4x-3^4)/((-3^2)^3)`

`(-3^4x-3^4)/((-3^2)3)=(3^4(-x-1))/((-3^2)3)`

`=(-3^4(x+1))/((3^2)3)` ( by using the property
`(a^m)^n=a^(mn)` )

`=(-3^4(x+1))/(3^6)`

`=(-(x+1))/(3^6.3^(-4))` ( by using the property
`a^m=(1)/(a^(-m))` )

`=(-(x+1))/(3^(6-4))` ( by using the property
`a^m.a^n=a^(m+n)` )

`=-((x+1))/(3^2)`

`=-((x+1))/(9)`

Therefore
`(-3^4x-3^4)/((-3^2)^3)=-((x+1))/(9)`

Therefore the solved given expression is

`(-3^4x-3^4)/((-3^2)^3)=-((x+1))/(9)`