Answer:
4.38
Explanation:
There 15 different color crayon in a box.
We will enumerate the crayon from 1 to 15
Let Xi be the indicator random variable for the event that the ith crayon is among the set of 5 crayon.
E[Xi] = Pr(at least one type i crayon is in the set of 5)
E[Xi] = 1 - Pr(no type i crayons are in the set of 5)
= 1 - (14/15)^5
The expected number of crayon is
E(summation of Xi for the 15 crayons where i = 1) = 25(1- (14/15)^5)
= 4.38