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Factored form of the given equation
6x2+2x-8=

User RanLearns
by
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1 Answer

6 votes

Answer:

(
x-1) and (
x+(4)/(3)) are the factors of the given equation

It can be written as
6x^2+2x-8=(x-1)(x+(4)/(3))

Explanation:

Given quadratic equation is
6x^2+2x-8=0

To find the factored form of the given equation :


6x^2+2x-8=0

By using the formula for quadratic equation
ax^2+bx+c=0 then the solution is
x=(-b\pm √(b^2-4ac))/(2a) where a and b are coefficients of
x^2 and x respectively


x=(-b\pm √(b^2-4ac))/(2a)

Substitute a=6, b=2 and c=-8 in the above equation we get


x=(-2\pm √(2^2-4(6)(-8)))/(2(6))


=(-2\pm √(4+192))/(12)


=(-2\pm √(196))/(12)


=(-2\pm 14)/(12)


x=(-2\pm 14)/(12)

Therefore
x=(-2+14)/(12) and
x=(-2-14)/(12)


x=(12)/(12) and
x=(-16)/(12)


x=1 and
x=(-4)/(3)

Therefore (
x-1) and
(x+(4)/(3)) are the factors of the given equation

It can be written as
6x^2+2x-8=(x-1)(x+(4)/(3))

User Love Gupta
by
8.1k points

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