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Solve the system of equations

3x + 4y + 2z = 1
4x + 6y + 2z = 7
2x + 3y + z = 11

User Eudemonics
by
7.7k points

2 Answers

5 votes

Answer:

Hindi ko po alam yan sorry

User Eyalyoli
by
8.2k points
7 votes

Answer:

no solution

Explanation:


\left\{\begin{matrix}3x+4y+2z=1\\4x+6y+2z=7\\2x+3y+z=11\\\end{matrix}\right.

Rearrange


\left\{\begin{matrix}3x+4y+2z=1\\4x+6y+2z=7\\z=11-2x-3y\\\end{matrix}\right.

Substitute into one of the equations


\left\{\begin{matrix}3x+4y+2(11-2x-3y)=1\\4x+6y+2(11-2x-3y)=7\\\end{matrix}\right.

Apply the Distributive Property


\left\{\begin{matrix}3x+4y+22-4x-6y=1\\4x+6y+22-4x-6y=7\\\end{matrix}\right.

Apply the Inverse Property of Addition


6y+22-6y=7


\left\{\begin{matrix}3x+4y+22-4x-6y=1\\22=7\\\end{matrix}\right.

Rearrange variables to the left side of the equation


\left\{\begin{matrix}3x+4y-4x-6y=1-22\\22=7\\\end{matrix}\right.

Combine like terms


\left\{\begin{matrix}-x-2y=1-22\\22=7\\\end{matrix}\right.

Calculate the sum or difference


\left\{\begin{matrix}-x-2y=-21\\22=7\\\end{matrix}\right.

Rearrange like terms to the same side of the equation


\left\{\begin{matrix}-x=-21+2y\\22=7\\\end{matrix}\right.

Divide both sides of the equation by the coefficient of variable


\left\{\begin{matrix}x=21-2y\\22=7\\\end{matrix}\right.

Based on the given conditions, the (system of) equation(s) has


no\ solution

I hope this helps you

:)

User TafT
by
8.1k points

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