Question

If an aluminum skillet with 10.0 inch diameter weighs 3.00 pounds, What volume of aluminum does it contain? (The density of aluminum is 2.70g/cm3, 1.00 pound = 453.6g)

Answer 1

The answer to your question is 504 cm³

Step-by-step explanation:

Data

diameter = 10 in

mass = 3 pounds

density = 2.7 g/cm³

1 pound ----- 453.6 g

Process

1.- Convert pounds into grams using proportions

1 pound --------------- 453.6 g

3 pounds ------------ x

x = (3 x 453.6) / 1

x = 1360.8 g

2.- Calculate the volume of the skillet

Formula

density =
`(mass)/(volume)`

Solve per volume

`volume = (mass)/(density)`

Substitution

`volume = (1360.8)/(2.70)`

Simplification and result

volume = 504 cm³