Question

How to solve 5(2b-3)-1(11b+1)=20

Answer 1

b = -36

Explanation:

Start by distributing both th 5 and the negative 1 into their corresponding parentheses.

((5*2b)-(5*3)) > (10b - 15)

((-1*11b)+(-1*1)) > (-11b - 1)

so you have:

10b - 15 - 11b - 1 = 20

Next you would Combine like terms to get:

-b - 16 = 20

Add the 16 to both sides

-b = 36

and divide each side by -1

b = - 36

hope this helps