Register
One day in October 2005, you could exchange $3 for about 2.5 euros. How many dollars would you have needed to get 8 euros?
80.8k views
3 votes
One day in October 2005, you could exchange $3 for about 2.5 euros. How many dollars would you have needed to get 8 euros?

User Dylan James McGannon
by
5.8k points

1 Answer

0 votes
10 because 3$ times two is 5 dollars in euros, and 4 dollars is 3 dollars in euros. Therefore if you add 6 and four together you get a total of 10 dollars
User CSharpRocks
by
5.4k points
Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

5.6m questions

7.3m answers

Other Questions

What is the value of x? (-4) - x = 5
Can someone help me with 5??? ASAP?
1/7 + 3/14 equivalent fractions
185g in the ratio 2:3
(3x1,000,000)+(3x100,000)+(2x100) what is this number written in standard form?
Link Copied!