Question

SOLVE: High school precal

Answer 1

Tbh idk I just need help passing a class

Answer 2

The anser is
`ln(64y^2)`

Explanation:

• There are two logarithm properties one should take into account to understand that
  `2ln8+2lny` and
  `ln(64y^2)` are equal expressions.
• The first property refeers to exponentials:
  `ln(x^n)=n*{lnx}`.
• The second property is the follow:
  `ln(x.y)=ln(x)+ln(y)` (distributive property of the logarithm of a product).
• Applying these two properties to the expression
  `ln(64y^2)` results as follows:

1. 
   `ln(68y^2)=ln(8y)^2` because
   `8*8=64`. Then, applying the first property means that
   `ln(8y)^2=2*{ln(8y)}`
2. Finally, applying the second property of logarithms to the logarithm of a product implies:
   `2*{ln(8y)}=2*[ln(8)+ln(y)]= 2*{ln(8)}+2*{ln(y)}`, which is the expression we needed to arrive.