Question

A circle has a diameter

with endpoints at (10, 8)
and (5, 4). What is the
circumference of this
circle?​

Answer 1

The answer to your question is below

Explanation:

Data

A (10, 8)

B (5, 4)

Process

1.- Find the length of the radius

d =
`\sqrt{(5 - 10)^(2) + (4 - 8)^(2)}`

d =
`\sqrt{5^(2) + 4^(2)}`

d =
`√(25 + 16) = √(41)`

radius =
`√(41) / 2`

2.- Find the center

Xm =
`(10 + 5)/(2)`

Xm =
`(15)/(2)`

Ym =
`(8 + 4)/(2)`

Ym =
`(12)/(2) = 6`

Center = (15/2 , 6)

3.- Write the equation of the circle

(x - 15/2)² + (y - 6)² =
`(41)/(4)`