Question

What mass is 2.4E25 molecules of NaHCO3?

Answer 1

Step-by-step explanation:

Mole = no. Molecules/6.02×10^23

Mole = (2.4×10^25)/(6.02×10^23)

Mole = 39.87mole

Molar mass of NaHCO3 is

= 23 + 1 + 12 + 3(16)

= 84g/mol

Mole = mass/molar mass

Mass = Mole × molar mass

Mass = 39.87 × 84

Mass= 3348.84g