Question

A 0.500 kg rock is whirled in a vertical circle of a radius 0.60 m . the velocity of the rock at the bottom of the swing is 4.0 m/s . what is the acceleration

A 3.3 m/s^2
B 26.6 m/s^2
C 13.3 m/s^2
D 6.6 m/s^2​

Answer 1

Step-by-step explanation:

Centripetal acceleration is:

a = v² / r

a = (4.0 m/s)² / 0.60 m

a = 26.6 m/s²