137k views
0 votes
If the pure water in the left arm of the U-tube is replaced by a solution more concentrated than the one in the right arm, what will happen?

User JanLikar
by
4.6k points

2 Answers

7 votes

Final answer:

If the pure water in the left arm of the U-tube is replaced by a more concentrated solution, water will move from the left arm to the right arm due to osmosis.

Step-by-step explanation:

If the pure water in the left arm of the U-tube is replaced by a solution more concentrated than the one in the right arm, the water will move from the left arm to the right arm. This is because of the process known as osmosis. Osmosis is the movement of solvent molecules from an area of lower solute concentration to an area of higher solute concentration through a semi-permeable membrane. In this case, the more concentrated solution in the right arm will attract the water molecules, causing them to move from the left arm to the right arm until equilibrium is reached.

User Bruh
by
4.3k points
5 votes

Answer:

Water will move from left side to right side in the U-tube

Step-by-step explanation:

Osmosis refers to the movement of the solvent molecule (water) from a low concentration of the solute to high concentration of the solute or from a high concentration of water to the low concentration of water.

The experiment was performed to demonstrate the osmosis using a permeable membrane which allows the movement of the solvent particles and U-tube.

When the left side of U-tube contained pure water and the right side contained concentrated solution with a high amount of the solute and low amount of water then the water will move from the higher concentration to lower concentration or from left side to right side.

Thus, Water will move from left side to right side in the U-tube.

User Jasonfealy
by
4.1k points