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X to the second power plus eight x plus 25 equal zero

User Borodin
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1 Answer

3 votes

For this case we must solve the following quadratic equation:


x ^ 2 + 8x + 25 = 0

We solve the equation using the quadratic formula:


x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2a}

Where:


a = 1\\b = 8\\c = 25

Substituting we have:


x = \frac {-8 \pm \sqrt {8 ^ 2-4 (1) (25)}} {2 (1)}\\x = \frac {-8 \pm \sqrt {64-100}} {2}\\x = \frac {-8 \pm \sqrt {-36}} {2}

By definition we have that
i ^ 2 = -1, then:


x = \frac {-8 \pm \sqrt {36i ^ 2}} {2}\\x = \frac {-8 \pmi \sqrt {36}} {2}\\x = \frac {-8 ± 6i} {2}\\x = -4 \pm3i

We have two complex roots:


x_ {1} = - 4 + 3i\\x_ {2} = - 4-3i

Answer:


x_ {1} = - 4 + 3i\\x_ {2} = - 4-3i

User Ivo
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