Question

For the chemical reaction 2 KI + Pb ( NO 3 ) 2 ⟶ PbI 2 + 2 KNO3 what mass of lead(II) iodide is produced from 2.89 mol of potassium iodide

Answer 1

The answer to your question is 1.45 moles of PbI₂

Step-by-step explanation:

Reaction

2KI + Pb(NO₃)₂ ⇒ PbI₂ + 2 KNO₃

Process

1.- Check if the reaction is balanced

Reactants Elements Products

2 Potassium 2

2 Iodine 2

1 Lead 1

2 Nitrogen 2

6 Oxygen 6

This reaction is balanced

2.- Calculate the moles of Lead (II) iodine using proportions and the coefficients of the balanced reaction.

2 mol of KI ------------------ 1 mol of PbI₂

2.89 mol of KI --------------- x

x = (2.89 x 1) / 2

x = 1.45 moles of PbI₂