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5 votes
PLZ HELP, WORTH 20 PTS.

Determine the approximate value of t.


2.03

5.54

6.4

15.45

PLZ HELP, WORTH 20 PTS. Determine the approximate value of t. 2.03 5.54 6.4 15.45-example-1

2 Answers

3 votes

Answer:

B. 5.54

Explanation:

To find out what t is, use the formula t=√[r² + s² - 2rs * cos(T)].

t = √[4² + 5² - 2(4(5)) * cos(75)]

t = √[16 + 25 - 8(5) * cos(75)]

t = √[41 - 40 * cos(75)] (For convenience, 40 * cos(75) has been approximated.

t = √[41 - 10]

t = √31

To approximate a square root subtract the lower square (25) from 31 and put that over the higher square (36) minus the lower square (25).

t ≈ 5 + (31 - 25)/(36 - 25)

t ≈ 5 + 6/11

t ≈ 5 6/11 ≈ 5.54, so B is the answer.

User Reinier
by
5.6k points
7 votes

The approximate value for t is 5.54

Answer: Option B

Explanation:

The law of cosines generalizes the Pythagorean formula to all triangles. It says that
c^(2), the square of one side of the triangle, is equal to
a^(2)+b^(2) product times the cosine of the opposite angle. When the angle C is right, it becomes the Pythagorean formula.


c^(2)=a^(2)+b^(2)-2 a b \cos C

According to the given triangle in figure, the values are

a = 5

b = 4

c = t


\cos C=\cos 75^(\circ)=0.2588

Substituting all the given values in the formula, we get


t^(2)=5^(2)+4-(2 * 5 * 4 * 0.2588)


t^(2)=25+16-10.3527


t^(2)=41-10.3527=30.647

Taking square roots, we get the value for ‘t’ as below,


t=√(30.647)

t = 5.536 (approximately 5.54)

User Mauro Casas
by
5.3k points