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8. Write the slope-intercept form of the equation of the line graphed below. ​

8. Write the slope-intercept form of the equation of the line graphed below. ​-example-1
User Stonedauwg
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1 Answer

5 votes

Answer:

Explanation:

The equation of a straight line can be represented in the slope-intercept form, y = mx + c

Where c = intercept

Slope, m =change in value of y on the vertical axis / change in value of x on the horizontal axis

change in the value of y = y2 - y1

Change in value of x = x2 -x1

y2 = final value of y

y 1 = initial value of y

x2 = final value of x

x1 = initial value of x

From the graph,

y2 = 4.5

y1 = 0.5

x2 = 2

x1 = - 2

Slope,m = (4.5 - 0.5)/(2 - - 2) = 4/4 = 1

To determine the intercept, we would substitute x = 2, y = 4.5 and m= 1,

4.5 = 1 × 2 + c = 2 + c

c = 4.5 - 2 = 2.5

The equation becomes

y = x + 2.5

User Chris Richner
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