Question

The density (mass/volume) of aluminum is 5.26 slug/ft^3. Determine its density in SI units. Use an appropriate prefix.

Answer 1

Answer : The density of aluminum in S.I units is,
`2710.89kg/m^3`

Explanation :

Conversion from slug to kilogram is:

1 slug = 14.5939 kg

Conversion from feet to meter is:

1 feet = 0.3048 m

The S.I unit of density is, kilogram per meter cube or, kg/m³

Given:

Density of aluminum =
`5.26\text{ slug}/ft^3`

By using conversion, we get the S.I unit of density of aluminum.

Density of aluminum =
`5.26\text{ slug}/ft^3* \frac{145939kg}{1\text{ slug}}* ((1ft)/(0.3048m))^3`

Density of aluminum =
`2710.89kg/m^3`

Thus, the density of aluminum in S.I units is,
`2710.89kg/m^3`