Answer:
The solution is (
,0)
The given system of equations have only one solution
(
,0)
Explanation:
Given equations are
![1.5x+2y=11\hfill (1)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/resgxklx7vbryfpumkj69lm7ag0qd33wo2.png)
and
Now to find the number of solutions to the given system:
Multiply the equation (1) into 3 we get
![4.5x+6y=33\hfill (3)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/g6vrrz3dsr9kzyilx1bkl3f5wi5mujfqkb.png)
Subtracting the equations (2) and (3) we get
4.5x+6y=33
3x+6y=22
__________
1.5x=11
![x=(11)/(1.5)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/vtlrfl3c6vzqehspxmgie06lr6cdgtjb6r.png)
Substitute the value of x in equation (1) we get
![1.5((11)/(1.5))+2y=11](https://img.qammunity.org/2021/formulas/mathematics/middle-school/4vi38qor8kpjlyi08pf3zftauqhw788afg.png)
![11+2y=11](https://img.qammunity.org/2021/formulas/mathematics/middle-school/f50sc2s2zbbsjmz6bmdkhycdj39ixh6ua6.png)
2y=0
Therefore y=0
Therefore the solution is (
,0)
The given system of equations have only one solution (
,0)