Question

-2x + 22 < 18

It is an inequality

Answer 1

`x > 2`

Explanation:

`\begin{bmatrix}\mathrm{Solution:}\:&\:x > 2\:\\ \:\mathrm{Interval\:Notation:}&\:\left(2,\:\infty \:\right)\end{bmatrix}`

Given:

-2x + 22 < 18

Solve:

`\mathrm{Subtract\:}22\mathrm{\:from\:both\:sides}`

`-2x+22-22 < 18-22`

`\mathrm{Simplify}`

`-2x < -4`

`\mathrm{Multiply\:both\:sides\:by\:-1\:\left(reverse\:the\:inequality\right)}`

`\left(-2x\right)\left(-1\right) > \left(-4\right)\left(-1\right)`

`\mathrm{Simplify}`

`2x > 4`

`\mathrm{Divide\:both\:sides\:by\:}2`

`(2x)/(2) > (4)/(2)`

`\mathrm{Simplify}`

`x > 2`

~Lenvy~

Answer 2

Solving for x;

-2x + 22 < 18

Get rid of constants:

-22 -22

-2x < -4

Isolate x, by dividing by -2 from both sides since the inverse operation of multiplication is division, and remember when dividing or multiplying by negative integers, you flip the inequality symbol around:

÷-2 ÷-2

x > 2