Answer:
The sample mean is
and the sample median is 0.56
Explanation:
The sample mean
of observations
is given by
![\bar{x}=(\sum x_i)/(n)](https://img.qammunity.org/2021/formulas/mathematics/college/lb6ecq7kpsby575iisqeg551xvv00mrcgq.png)
Applying the above definition we get that
The sum of these 15 sample observations is
![\sum x_i = 0.21+\:0.22+\:0.26+\:0.30+\:0.34+\:0.42\:+0.55+\:0.56+\:1.43+\:1.70+\:1.84+\:2.20+\:2.25+\:3.06+\:3.26\\\\\sum x_i =18.6](https://img.qammunity.org/2021/formulas/mathematics/college/o2qqnwtoemqysn3o5ciwg5qsichr0yompv.png)
and the sample mean is
![\bar{x}=(18.6)/(15)=1.24](https://img.qammunity.org/2021/formulas/mathematics/college/s6o6sorwmonoi298dzqs6r7gndgrxrf02x.png)
The sample median is obtained by first ordering the n observations from smallest to largest (with any repeated values included so that every sample observation appears in the ordered list). Then,
Sample median = The single middle value if n is odd =
![((n+1)/(2) )^(th)](https://img.qammunity.org/2021/formulas/mathematics/college/xe3b3cog1xgzitrgbg9dlenf57644xxv4x.png)
Sample median = The average of the two middle values if n is even = average of
and
![((n)/(2)+1 )^(th)](https://img.qammunity.org/2021/formulas/mathematics/college/1qhvmjzaz0zxb92aai46rp2vrtcwchngvd.png)
Applying the above definition we get that
The data is already ordered and n = 15 so,
Sample median =
= 0.56